X^2+2(x-4)=3x-8

Solution for X^2+2(x-4)=3x-8 equation:

X^2+2(X-4)=3X-8

We move all terms to the left:

X^2+2(X-4)-(3X-8)=0

We multiply parentheses

X^2+2X-(3X-8)-8=0

We get rid of parentheses

X^2+2X-3X+8-8=0

We add all the numbers together, and all the variables

X^2-1X=0

a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2}
=1
$